The calculator will generate a step-by-step explanation on how to obtain the result. This calculator find and plot equations of parallel and perpendicular to the given line and passes through given point. Once you have the intersection point, combine it with the Normal3 we calculated at the beginning to get the intersection line. Parallel and perpendicular line calculator. Now if we find the intersection of those two lines, it will give a point which occurs on both lines, which means it also occurs on both planes: Symbolab is the best step by step calculator for a wide range of physics problems, including mechanics, electricity and magnetism, and thermodynamics. Line2 = (line2start, line2start + line2dir) That gives use two lines: line1 = (line1start, line1start + line1dir) That's just the normal times the offset: line1start = Normal1 * Offset1 Compute answers using Wolframs breakthrough technology & knowledgebase, relied on by millions of students & professionals. So now we need the origin of each of these lines. We can get the direction of each line as the cross product of our new plane's normal with the original normal: line1dir = Normal1 × Normal3
So we want to calculate what those 2 lines are. Now if we look at the existing planes from the perspective of that direction, our 2 planes look like 2 lines, because we're viewing them both edge-on. Start with the cross product of the normal vectors of the 2 planes (Normal1 and Normal2) to get a direction of the intersection line (Normal3): Normal3 = Normal1 × Normal2 Symbolab is the best integral calculator solving indefinite integrals, definite integrals, improper integrals, double integrals, triple integrals, multiple integrals, antiderivatives, and more. The 10 major concepts are: number, ratio, algebra, geometry, analytical. So I came up with a more intuitive approach. Shormann Interactive Math Product Questions Recommended Calculators Recommended. I tried the systems of equations approach posted by multiple people, but dealing with division by zero made things really messy. From the coefficients of x, y and z of the general form equations, the first plane has normal vector $\begin.
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